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Hierbei ist P 1 k=0 a k absolut konvergent L osungsvorschlag zu a) (i) Ist jxj1, dann ergibt sich f n(x) = x2n 1 x 2n = 1 1 x!(a) X∞ n=0 c n(−2)n Yes If P ∞ n=0 c n4 n is convergent, then the radius of convergence for the power series P ∞ n=0 c nx n is at least 4 Therefore the interval of convergence contains 2 (b) X∞ n=0 c n(−4)n No Consider the power series XX X g S \ P ʁE t @ ^ V X ^ I C u Q i h L X g E Z K j ܂ ĊF l ̗\ z ʂ A P ʂ͂ ́u V I ̃Q ݂̍ v \ o r n Ɍ v ܂ B ܂Łu n } Ζʔ 񂾂낤 ǁA Ƃ ɂ ȁv Ƃ C W ̂ l b g Q Ƃ W ̊_ Y Ɏ A ȒP ȑ A Q ̃l b g \ A ăT o ̋ Q S ԑΉ ̃ e i X ܂ŐS z ̍s ͂ ΂ɂ ē { ́u l b g Q Ŏҁv ̐ 𖾂炩 ɑ ₵ ܂ Ă ꂽ ̂ł i ΁j B ۂq o f Ƃ Ă \ 񕪂̖ʔ ̂ŃI t C ̂P l v C ł 瑻 Solved 8 Points Start With P N 1 X Npn X Xpkx Chegg Com J a p a n

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