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(4)(3)(2)(1) P(3) = (5)(5)(5) (5) (1) (3)(2)(1) 4 P(3) = = 25 16 This is the same answer found in a binomial distribution table for 4 trials, using 3 successes and a probability of 5, or 1/2, on each trial The table eliminates the need for the computation and is very useful when more than one problem or a multy step problem isü ´ í r í ñ r î ì ì õ î r ð ï î r õ ô ô î í ó W ì ì î ð W ì ì ç ¦ à u ^ Ñ é } » Ó Æ Ç è ñ í ñ Ç è ñ ;W M X X A similar calculation shows W M Y Y Thus º³ c c 1 11 ˆ ˆ BV DNE EX X X Study Resources Main Menu;



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