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Q O Q O D S D P R A g t F X ^ ̉ ɂ Y @ A ̒ʂ v w Łu S ̃q g v ֓ǂ Ă ܂ B w Ԃ Ƃ B Ƃ ŁA ␢ E O o l B V ^ R i E C X ͐l ނɂƂ čő ̊ @ ɂȂ Ă B { ł l ̏W ܂ C x g ͒ ~ A ό Ƃ͂ Ƃ A e ʂŌo ϊ ܂ŃX g b v Ă B ꂩ ǂ Ȃ邩1 day ago · !u Ã4Ú¥«É¨ö0Á ƒ»T ®Zhª!ÁÕ AêíÃuÿ w) õcφ¨;žï¤˜JRf @ •Ø'i¤,™ #MÅ v‹ið± _è´ßë ìŠÅcÈ¢¥ ³kAIö3ùÇý²(FûÙÿ¦Ä ³ÿ~Š3/ÿݸ ïP IGa¡é Â\æ¯GM )Øû¿ —4j RˆUÙ7 ®Ûm¯ïY¡Í &} M*ÓX¾¡jÏ =™±9R¡m} ^&¶R•‡ 'eÖçkÚ{Ðì€T¯MþVW) E JŽÃ ¬÷¨º w Úö©—o¹Ì()i t n i t n N n N n N n N n N n A e n B e n q t N q t q t q t Ω = 1 1 1 1 3 2 1 sin sin 3 sin 2 sin 1 π π π π M M, (7) where Ω =2~sinn 2()N 1 n ω π As we mentioned last time, these modes are essentially standing waves Let's see that this is the case by writing Eq
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Differentiate f(x,t) = cos(x t 2) with respect to t We must use the chain rule with x held constant Thus, Example Differentiate the following function with respect to y To do this, we of course view x as a constant We see that the product rule must be used since we have aþ Ä ³ Ñ · d = H " Ô Þ s ¤ H y ( = ¥ J Ü r z ^ y 2 F ¯ ½ ¢ Ê 5 v 2 F þ o g } Ê 5 y t ¥ J Ü 2 F þ o g } Ê 5 W 2 F þ o g E ¤ ¥ 2 F { ¥ g }>í >Ý>á >í >Þ>ã ¥ ± Û >í>Ý>á p ¸ ± Û >í>Þ>ã & ¸ ± Û >í>Ý>â ¥ ± Û >í>ß>â 1 0i Ç'¨ · µ ·7r >î>Ý>â
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Ae x Be 5x with derivative y Ae x 5Be 5x Evaluating at x 0, we have 4 A B 1 A 5B Solving this pair of equations, we get A 19 4 and B 3 4, so our solution is (1213) y 19 4 e x 3 4 e 5x Example 124 A function x x t satisfies the differential equation (1214) x 2x 15x 0 Under what conditions on the values of x at t 2 0 will this function decayP q ^ s !ç ô>Þ>Ô>Þ>Ü>Þ>Ü>Õ º Ø ¹ b>ß>Ý>Ô>Þ>Ü>Ý>å>Õ º Ø ¹ b>ß>Ü º Ø \ >á>ã >á>Ý >ß>å >ä>Þ >ã>à >ä>â >Ü >Þ >Ý s g s6Û Û /'¼>Ì>Ý>Ü >â >Ý>ß u*Ë >Ü >Ý >Þ >Ü >Ý >Ü fífþ Ú >á >Ý>ã >Ý>Ý 0£ >Ý>á>à>Ý>á>Þ >Ý>á>Þ >ß a b a* xfÿ g x \ h f·f·h fÿ4# º Ø g Æ x m*ñ >Ý>Ô>Ý>Õ p#Õf·f
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If X = F(T) and Y = G(T) Are Differentiable Functions of , T Maharashtra State Board HSC Science (General) 12th Board Exam Question Papers 231 Textbook Solutions Important Solutions 3696 Question Bank Solutions Concept Notes & Videos 571 Time Tables 24 SyllabusInterstate/Highway Street Bike Path Spearfish Creek å ½ ¾ ¿ À Á Â é « % k ° ² ³>Þ>ß Ê 5 >Þ>Þ>ä>äHwH H Ht>Ý>ß>â Ê5 5 É>à>Þ>ß>ä,¡F·,Þ>à>à £#ã,À#Z p>Ý>Þ>Ü>Þ j £>ß>á>Ü"â $>Ì Q >à>Ý>ä>Ü ¥6ë>à>á>ä' N>Ì M%?>à>Ý>â>à>ÿ>õ>û>ú>á>ã>Þ, £>Ì F Ç>á>Ý>á>ÞFïFÛFúFç
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Solution for Let g(x) = (t) dt, where f is the function whose graph is shown y f (a) Evaluate g(0), g(4), g(8), g(12), and g(24) g(0) = 0 g(4) = 2 9(8) =T 6 p ,´h9c ¡n/ ,´ ç ¼ fb¼ Ä " éb¼gÿ m h9c 3 dÛq 0}6 "d Èfp @# 7 Ã7©7i ¼q gý Î Ð#f~ " çgÿh9c 3 Î Ð ;îõ,´nØlÚ Öq >p à nØ Ã ó8 > 1 Ã#f~§ Ï å ä B B1 B1!¥ 2Õ1 0 !¥ !ª0 9Ô H o " H ;
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