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¨àµë ¤¢ C" X^"v
¨àµë ¤¢ C" X^"v-And the last step is just to add a to both sidesJ c " â K n \ » À 6 c Ó 6 @ r  @ ` U I ² & @ ¼ n @ Þ À " â ö ¬ õ n ö
A-c=m(x-a) then you would divide both sides by mÁ } v / v v v ^ Á v ^ µ v u Ç Á X / v } v } P v ( } } µ } v U } r } µ } v v µ } v U Z µ v & o u ^ } Ç } À Z v } d Æ ( o u u l§ 52.24 ("PSD/NSR Regulations"), for fuel 1 gas combustion devices and fluid catalytic cracking unit catalyst regenerators for NOx,
( ( D i ( ( X } Á v } Z X v i X P } À E V } v U ^ µ v D^ µ v X } v } Z X v i X P } À E ^ µ i W Z W Z& r í î W ì ì WD hC F Ý 2 " S € X ¾ ¿ _ ± ž D w Ý ² õ # ˆ y Þ ú N 2 ç g O Ÿ B c º 0 n ¥ ÷ ?Hope this helped :D
So your answer is (a-c/m)+a=xJ º = ì à ¬ r ® = q ë œ Ö ' q l Æ é Ž q ‡ â 1 € v Ï þ Ò ï N Ö L À ¨ ¤ € D ¼ ð b 3 t í á d ' þ ³ Ä ó É ò > Ý { l 7 1 ¿ ± & ¬ ä Û / b ¤ ¢ n !First you would multiply both sides by x-a
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